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ok so which method do you think we should use
:D My favorite!
Do you have this Ari?
well we're not gonna answer it for you, but we'll help
We shall guide you along like a little lamb.
ok so if we're using substitution, what's our first step
So we have \[x-y=16\] \[2x+y=2\] We are going to want to isolate one of the variables in one of the equations. Can you do that for us?
Lets use the first equation to isolate x.
take x - y = 16. we're gonna solve for x ok? and to do that, you just gotta add y to both sides
x-y=16 You would move the y over to the right side of the equation. x=y+16
then you're going to take that and substitute it for x in the second equation
2x + y = 2 2(y + 16) + y = 2
Where there is an x in the second equation, plug in the value that you found.
I'm gonna head out, I think I may be confusing more than helping.
aw ok :/
now you have distribute the 2
have to*
so what do you get once you do that
2(y + 16) + y = 2 you multiply the 2 with the y and the 2 with the 16
yea 2(y + 16) + y = 2 2y + 32 + y = 2 now combine like terms
do you know what your like terms are
2y and y are your like terms..so add them
it is 3y 3y + 32 = 2 now you have to get y by itself. do you know how to do that?
well first you have to subtract 32, but yea. you gotta divide too. can you tell me what y equals?
did you just guess
so why do you think it's 12
yes, it is totally wrong lol 3y + 32 = 2 subtract 32 from both sides, then divide both sides by 3
@AriPotta
yes, from 2. you couldn't subtract it from 3y even if you wanted to. they're not like terms.
yes. now divide
yes! now we can substitute that into the first equation to solve for x x - y = 16 x - (-10) = 16 can you tell me what x equals?
yep!
do you understand this better now?
@AriPotta much better!
:] good luck~
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