Question

need some assistance sin(θ-8π)

Answer 1

sin(x) = sin(x+2pi*n)

Answer 2

where n is {...-3,-2,-1,0,1,2,3...}

Answer 3

so sin(x+8pi) = sin(x+6pi) = sin(x+4pi) = sin(x+2pi) = sin(x)

Answer 4

so sin(x-8pi) = sin(x-6pi) = sin(x-4pi) = sin(x-2pi) = sin(x)

Answer 5

ok but the answer for this question is -2 / square root of 13

Answer 6

did they give you a theta?

Answer 7

\[sin(\theta+8\pi)=sin(\theta)\]

Answer 8

plug in theta to get the answer

Answer 9

you with me @darkhound ?

Answer 10

sort of a strange answer if the question is sin(theta) = -2/sqrt(13) then theta is a very "strange" angle, of which most people would use a calculator instead of deriving it.

Answer 11

but the answer is sin(θ-8π)= -2/sqrt(13)

Answer 12

write the question exactly as its asked

Answer 13

you fall asleep typing?

Answer 14

given that tanθ=2/3 and θ is in the 3rd quadrant.without evaluating the angle θ,find the exact values of

a)cos(-θ)
b)sin(-θ)
c)sin(θ-8π)

Answer 15

no

Answer 16

lol this is much different than just sin(x-8pi)

Answer 17

ok but u know how to solve it?

Answer 18

yes

Answer 19

ok thanks

Answer 20

soh cah toa says that tan(theta) = opposite over adjacent, and thus you have a triangle like this

so
2^2+3^2=c^2
so c= sqrt(13)
so hypotenuse is sqrt(13)
soh says sin = opposite of hypotenuse
so sin(theta) = -2/sqrt(13) because theta is in quadrant 3

Answer 21

hope this helps, brb taco bell:)

Answer 22

so this is the answer for c right?

Answer 23

yes part c) because sin(theta-8pi) = sin(theta)

Answer 24

= sin(theta-(2345670*10^53)pi)

Answer 25

how come is -2?

Answer 26

are u still there zzr0ck3r