What is the length of ac ? Round to the nearest hundredth.
distance formula
d=√(x1-x2)²+(y2-y1)² d=√(-1-3)²+(-2-2)² is that right ? im not sure how to find x and y
its not right
lets do step by step. first tell me the coordinates of points A and C : A = ? C = ?
A-(-1,3) C-(2,-2) ?
A correct. C wrong
oops ! im wrong, you're correct actually :)
okkk (:
A (-1, 3) C (2, -2) x1 y1 x2 y2
apply distance formula now
\(\sqrt{(x1-x2)^2+(y1-y2)^2}\)
d=√(x1-x2)²+(y1-y2)² d=√(-1-2)²+(3-(-2))² d=√(-3)²+(5)² d=√9+25 d=√34
perfect !
Okkk (;. Soo how would i round it to the nearest tenth ?
sorry hundreth
plug it in ur calculator
what do u get when u take square root of 34 ?
oopss i forgot that part. Its 5.83 (: . ! ii Got It . THanksss Sooo Much ! 'ii Leanred something new !
nice :)))
ii have one more question on my assignment. Does coordinates on a triangle tell you what kind of triangle it would be ?
would it be scalene because they all have diferent points ?
know what, every point in grid will have different numbers.
so having different points is okay :) it wont give us any clue about the kind of triangle
we need to calculate distance of all 3 sides, and see
Ohhh Yess .. ^^That makes sense . ... how do i do that ?
use distance formula 3 times, and find the distance of each side
start with the finding the length of left side joining points : (-10, 8) and (-10, 3)
apply distance formula for those two points
okkik . ill do it paper and be back in a sec.
take ur time :) il he here
*be
so i got (-10,8)(-10,3) √5 (-10,8)(-6,5) √-1 (-10,3)(-6,5) √-6
check ur signs again
you would never get a negative sign inside radical, as these are lengths
im not sure what i did wrong because i did this (-10,8)(-10,3) x1 y1 x2 y2 d=√-10-(-10)+(8-3) d=√0+5 √5 (-10,8)(-6,5) d=√-10-(-6)+(8-5) d=√-4+3 √-1
Below correct way, see if it helps :- (-10, 8)(-10,3)\ \(\sqrt{(-10--10)^2+(8-3)^2} \) \(\sqrt{(0)^2+(5)^2} \) \(5\) (-10,8)(-6,5) \(\sqrt{(-10--6)^2+(8-5)^2} \) \(\sqrt{(-4)^2+(3)^2} \) \(\sqrt{16+9}\) \(\sqrt{25}\) \(5\) (-10,3)(-6,5) \(\sqrt{(-10--6)^2+(3-5)^2} \) \(\sqrt{(-4)^2+(-2)^2} \) \(\sqrt{16+4}\) \(\sqrt{20}\) \(4.47\)
looks u forgot to square inside the radical, other than that ur work is pretty good :)
oohhhh. i had the right numbers and process i just forgot to square it ! ... Stupid mistake -_-... But it would be isoclese right ? because it has 2 equal sides ?
yes it is isosceles !!
Okkk Greaat. Your Great ! Thankss Againnn (:. i Got Another 100% Due to your help ! ... Thanks sooo much ! Welp Time for another assighnment !
you deserve 100% you're very good in math !! good luck for another 100% :)
Join our real-time social learning platform and learn together with your friends!