What is the mass of 1.7 × 1023 atoms of zinc (Zn)?
Please Explain! i dont understand
you need to do a conversion. From the periodic table you can get the molar mass of Zn, which is the number of grams of zinc in one mole of zinc (6.022x10^23 atoms) from that you can find what fraction of a mole of atoms 1.7 x 10^23 is, and use that fraction to determine the weight of the sample.
molar mass of Zinc is 65.4
#atoms x (mass/mole of atoms) a mole is Avagadro's number, 6.022 x 10^23, so #atoms x (mass/6.022 x 10^23 atoms)=mass
what fraction of a mole is 1.7 x 10^23 ?
where do I get the number of atoms from ?
you are given that you have 1.7 x 10^23 atoms of Zn in the problem
1.7x10^23 x (65.4/6.022x10^23) = mass?
right :) notice how the units cancel
18.46 !
\[1.7\times10^{23}\cancel{\text{atoms}}\times\left(\frac{65.4\text{grams}}{6.022\times10^{23}\cancel{\text{atoms}}}\right)\approx18.46\text{grams}\]it is important to keep track of the units.
good job :)
wow . thank you very much !
welcome :)
This diagram can be really helpful for these kinda problem :)
Thanks !
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