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Mathematics 8 Online
OpenStudy (anonymous):

simple maths balance eq.

OpenStudy (anonymous):

\[As_{2}S_{5} + HNO_{3} \rightarrow H _{3}AsO _{4} + NO _{2} + H _{2}SO _{4} + H _{2}O\]

OpenStudy (anonymous):

@saifoo.khan

OpenStudy (anonymous):

@JA1

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (ja1):

Ugh I don't know this sorry :3

OpenStudy (anonymous):

k thanks

OpenStudy (ja1):

No prob sorry I couldn't be of more help :)

OpenStudy (mathstudent55):

I can't see the latex code

OpenStudy (ja1):

As.2S.5+HNO.3→H.3AsO.4+NO.2+H.2SO.4+H.2O I put a period right before the number got small

OpenStudy (mathstudent55):

Why do you call it a simple _maths_ balance eq. Isn't this chemistry?

OpenStudy (ja1):

I was thinking that but I don't really know this stuff so I didn't want to give a wrong opinion.

OpenStudy (anonymous):

@mathstudent55 its chemistry if u see basically but adding no. is maths thats why i used eq. and its not simple

OpenStudy (loser66):

\[As_{2}S_{5} + HNO_{3} \rightarrow H _{3}AsO _{4} + NO _{2} + H _{2}SO _{4} + H _{2}O\] \[x(As_{2}S_{5}) + y(HNO_{3}) \rightarrow z(H _{3}AsO _{4}) +p( NO _{2}) +q( H _{2}SO _{4})+r(H _{2}O)\] LEFT SIDE RIGHT SIDE As 2x = z S 5x = q H y = 3z+2q+2r N y = p O 3y = 4z+2p+4q+r from which we obtain the homogeneous linear system 2x -z = 0 5x -q = 0 y -3z -2q -2r = 0 y -p = 0 3y -4z -2p -4q -r = 0 the augmented matrix for this system is: \[\left[\begin{matrix}2 & 0&-1&0&0&0&0 \\ 5 & 0&0&0&-1&0&0\\0&1&-3&0&-2&-2&0\\0&1&0&-1&0&0&0\\0&3&-4&-2&-4&-1&0\end{matrix}\right]\]

OpenStudy (loser66):

solve for that matrix by reduced row echelon form, you can get what you called "simple math balance" hehehe

OpenStudy (anonymous):

yoh thanks @loser66

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