Question

please help!!! Simplify the expression sqrt-16/(3-3i)+(1-2i)

Answer 1

a) -20-16i/9
b) 8+4i/15
c) 8-4i/15
d) -20-16i/41

Answer 2

\[\frac{ \sqrt{-16} }{ 3-3i + 1 -2i }\] Combine like terms in the denominator to get:
\[\frac{ \sqrt{-16} }{ -5i +4 }\] Now, since we have a negative under the radical, put an i in front and make the radical a positive 16. The square root of 16 is 4, so:
\[\frac{ 4i }{ 4-5i }\]

Answer 3

None of those answers look like mine. Are you sure you typed the problem accurately?

Answer 4

yes

Answer 5

retriceipe

Answer 6

retriceipener

Answer 7

azzwipe

Answer 8

@danny562 retype the equation including the brackets for the sqrt. Preferably use the equation button to write it clearly. As you have it typed vinnv would be correct.

Answer 9

\[\sqrt{-16} \over (3-3i) + (1-2i)\]

Answer 10

if that is it then vinny is correct the only thing left to do is multiply by a factor of one (hint:complex conjugate of the denominator)

Answer 11

Ah yes, I forgot about that, you would need to multiply the numerator and denominator by the conjugate of the denominator. As you can tell, my algebra is a little rusty sometimes