Question

Write an equation for the line that is parallel to the given line and passes through the given point. y = x + 8; (2, 16)

Answer 1

y = x – 6 is this it?

Answer 2

any line that is parallel to y=x+8 has an equation y=x+ k where k is some constant and it passes through (2,16)..put these number in place of x and y

Answer 3

16=2+K or 16=10

Answer 4

16=2+k
or k=14

Answer 5

so the equation is y=x+14

Answer 6

not one of my multible choices

Answer 7

Since the line is parallel to y = x + 8, equating it with y=mx+c we find slope m=1(since the coefficient of x is 1)
Now line passes through point (2, 16) . Thus
\[x_{1} =2, y _{1}=16\]
Eq of line in slope point form is given as
\[y-y _{1}=m(x-x _{1})\]
I.e. y- 16=1(x-2)
I.e. y- 16=x-2
I.e. y=x-2 + 16
I.e. y=x+14
Which is the required eq of the line

Answer 8

A. y = x

B. y = x + 6

C. y = x – 6

D. y = x + 6
this is my choices

Answer 9

is the point is (2,16)?

Answer 10

B and D of your option is same..

Answer 11

that is what it is on my home work

Answer 12

is the point is (2,16)? yes that is what it says

Answer 13

hmm...

Answer 14

thanks for your help

Answer 15

welcome...