what is the oxidation number of phosphorus in P
\(\Huge\bf\color{#FF0000}W\color{#FF4900}e\color{#FF9200}l\color{#FFDB00}c\color{#FFff00}o\color{#B6ff00}m\color{#6Dff00}e~\color{#00ff00}t\color{#00ff49}o~\color{#00ffDB}O\color{#00ffff}p\color{#00DBff}e\color{#0092ff}n\color{#0049ff}S\color{#0000ff}t\color{#2400ff}u\color{#6D00ff}d\color{#B600ff}y\color{#FF00ff}!\) That's phosphorus in elemental form, the oxidation number is 0
what is the oxidation number in chlorine in Cl03-
The total of \(\large\sf ClO^{3-}\) is 3- Oxygen is 2- 3- and 2- combined is 5- To cancel that out, the Cl has to be 5+
thanks that was right :)
actually it's \(\large\sf ClO3^-\) sorry :P but Cl is still 5+
what is the oxidation number of carbon in H2C2O4 and zinc in Zn(OH)4-2 and chlorine in ClO3-
nevermind the last one i already go that one
Correct explanation for ClO3- there are 3 O's which are 2-, thats 6- total, with the overal - charge that's 5-, So the Cl is 5+
Oke for \(\large\sf H_2C_2O_4\) we know that hydrogen is 1+, and oxygen is 2- we have 2x hydrogen so that's 2+, We have 4x oxygen so thats 8- to cancel the 8- what does the + needs to gain? divide that by 2 because we have 2 carbon atoms
thanks again! :)
so what do you think?
what is the oxidation number of antimony in Sb2O5
wait we were not finished with the last 3...
i already got the other one
what about the zinc in Zn(OH)4-2 and chlorine in ClO3- ?
i got that one too. lol
Oke then \(\large\sf Sb_2O_5\) O = 2- we have 5x O so thats 10- what does antimony needs to be?
i dont know lol
is it +5
the O is 10- to cancel that out we need Sb to be 10+ we have 2x Sb so what does Sb needs to be?
Yes 5+ is correct :) 10/2=5
sweet! im learning
awesome :P
what is the chlorine in ClO2
O = 2- so 2x O = 4- you probably know what Cl needs to be now :P
-2
No there is only 1 Cl
wait +3??
and is the oxidation number of lead in Pb =0 ??
Yes it's in elemental state Cl in ClO2 = 4+
thank you! im terrible at chemistry!
2 Ag+NiO2+H20------->Ag2O+Ni(OH)2 name the element oxidized and name the element reduced
could you post that in a new question? this one is getting long
what do you mean
I mean that's another question. This question is about oxidation numbers. You can close this question by clicking on the blue close button. Then ask the new question in the question box.
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