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Mathematics 10 Online
OpenStudy (anonymous):

[7.03] Identify the Exponent Law shown in the example below. a2a3 = a2+3 = a5 Power of a Product Power of a Power Product of Powers None of the Above

OpenStudy (oaktree):

Product of powers. It is \[(a^2)*(a^3)\]

OpenStudy (anonymous):

Thank You I will let you know if this is correct. Please dont leave yet

OpenStudy (oaktree):

If you say so.

OpenStudy (anonymous):

[7.03] Choose the correct simplification of the expression (5x4y2z2)(3x4y3z5). 15x16y6z10 15x8y5z7 8x8y5z7 8x16y6z10

OpenStudy (oaktree):

\[15x^8y^5z^7\]

OpenStudy (oaktree):

Just combine the constants in front and then add the exponents.

OpenStudy (anonymous):

Ohhh. Okay i have a few more if thats ok

OpenStudy (oaktree):

@Nurali Try to explain the answer, not just give it.

OpenStudy (anonymous):

I'm kinda getting the adding and subtracting . Just not the Multiplication and Division

OpenStudy (oaktree):

Multiplication is adding the exponents, division is subtracting them. That's all.

OpenStudy (anonymous):

Ohhh.

OpenStudy (anonymous):

[7.03] Choose the correct simplification of the expression (7ab3)2. 49ab6 49a2b5 49a2b6 14a2b6

OpenStudy (oaktree):

That's power to a power. Since you're raising the ENTIRE thing to a power. Think of it like this:

OpenStudy (oaktree):

\[(7ab^3)(7ab^3)\]

OpenStudy (oaktree):

Now you can see that you just add the exponents and multiply the constants.

OpenStudy (anonymous):

So that would be 49ab6 right

OpenStudy (nurali):

\[ (5x^4y^2z^2)(3x^4y^3z^5)\] \[ (5x^4*3x^4*y^2*y^3*z^5*z^2)\] \[5*3*x ^{4+4}*y ^{2+3}*z ^{5+2}\] \[15x^8y^5z^7\]

OpenStudy (anonymous):

Thank you @Nurali

OpenStudy (oaktree):

Yeah, that's right.

OpenStudy (anonymous):

Yay!

OpenStudy (nurali):

Anytime.

OpenStudy (oaktree):

Sorry, no, it's\[49a^2b^6\]

OpenStudy (anonymous):

[7.03] Choose the correct simplification of the expression (2x7y)2(y5)3. 4x7y10 4x9y10 4x14y16 4x14y17

OpenStudy (oaktree):

You forgot to add the powers on the a.

OpenStudy (oaktree):

OOPS.

OpenStudy (anonymous):

Ohhhh I see now

OpenStudy (anonymous):

Lol

OpenStudy (oaktree):

Okay. This next one is just like the last one, except it's a problem in a problem. Let's take it step by step.

OpenStudy (anonymous):

Ok

OpenStudy (oaktree):

First, do the power to a powers. \[(2x7y)^2 * (y^5)^3 = (2x7y)(2x7y)*(y^5)(y^5)(y^5)\]

OpenStudy (oaktree):

Can you simplify that?

OpenStudy (anonymous):

a little confused

OpenStudy (oaktree):

First do the 2x7y part. There's an imaginary exponent of 1 on top of each of them. What's 1+1?

OpenStudy (oaktree):

(wow, I feel stupid)

OpenStudy (anonymous):

lolllll

OpenStudy (anonymous):

2

OpenStudy (oaktree):

Oh, wait. Is that\[2x7y\]or \[2x^7y\]

OpenStudy (oaktree):

Because there's a significant difference.

OpenStudy (anonymous):

Second option

OpenStudy (oaktree):

OK. Nevermind, then!

OpenStudy (oaktree):

It's time to learn a shortcut.

OpenStudy (anonymous):

The one where the 7 is higher

OpenStudy (anonymous):

Lol Im ready

OpenStudy (oaktree):

Any time you have a problem of the form\[((some constant)*a^x*b^y)^c\]

OpenStudy (oaktree):

You multiply x and c as well as y and c, but take the constant to the c power. So it's\[(someconstant)^c*a ^{xc}*b^{yc}\]

OpenStudy (oaktree):

In this case, we have \[(2x^7y)^2\]

OpenStudy (anonymous):

Hmm? What would be the constant

OpenStudy (anonymous):

Oh

OpenStudy (oaktree):

Can you evaluate that? Just multiply the 2 by the exponents and take 2^2.

OpenStudy (oaktree):

And remember it's technically y^1.

OpenStudy (anonymous):

Ok so that would be 2

OpenStudy (anonymous):

Sorry im a little bit slow with math :c

OpenStudy (anonymous):

oh wait wouldnt that be 14 and 4 @oaktree

OpenStudy (oaktree):

Like \[4x^{14}y^2\]

OpenStudy (anonymous):

Ohh ok that makes a lot more sense

OpenStudy (oaktree):

:-)

OpenStudy (anonymous):

My question is a little different then this one

OpenStudy (anonymous):

Thank You @Oaktree

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