Mathematics
10 Online
OpenStudy (anonymous):
[7.03] Identify the Exponent Law shown in the example below.
a2a3 = a2+3 = a5
Power of a Product
Power of a Power
Product of Powers
None of the Above
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OpenStudy (oaktree):
Product of powers. It is \[(a^2)*(a^3)\]
OpenStudy (anonymous):
Thank You I will let you know if this is correct. Please dont leave yet
OpenStudy (oaktree):
If you say so.
OpenStudy (anonymous):
[7.03] Choose the correct simplification of the expression (5x4y2z2)(3x4y3z5).
15x16y6z10
15x8y5z7
8x8y5z7
8x16y6z10
OpenStudy (oaktree):
\[15x^8y^5z^7\]
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OpenStudy (oaktree):
Just combine the constants in front and then add the exponents.
OpenStudy (anonymous):
Ohhh. Okay i have a few more if thats ok
OpenStudy (oaktree):
@Nurali Try to explain the answer, not just give it.
OpenStudy (anonymous):
I'm kinda getting the adding and subtracting . Just not the Multiplication and Division
OpenStudy (oaktree):
Multiplication is adding the exponents, division is subtracting them. That's all.
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OpenStudy (anonymous):
Ohhh.
OpenStudy (anonymous):
[7.03] Choose the correct simplification of the expression (7ab3)2.
49ab6
49a2b5
49a2b6
14a2b6
OpenStudy (oaktree):
That's power to a power. Since you're raising the ENTIRE thing to a power. Think of it like this:
OpenStudy (oaktree):
\[(7ab^3)(7ab^3)\]
OpenStudy (oaktree):
Now you can see that you just add the exponents and multiply the constants.
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OpenStudy (anonymous):
So that would be 49ab6 right
OpenStudy (nurali):
\[ (5x^4y^2z^2)(3x^4y^3z^5)\]
\[ (5x^4*3x^4*y^2*y^3*z^5*z^2)\]
\[5*3*x ^{4+4}*y ^{2+3}*z ^{5+2}\]
\[15x^8y^5z^7\]
OpenStudy (anonymous):
Thank you @Nurali
OpenStudy (oaktree):
Yeah, that's right.
OpenStudy (anonymous):
Yay!
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OpenStudy (nurali):
Anytime.
OpenStudy (oaktree):
Sorry, no, it's\[49a^2b^6\]
OpenStudy (anonymous):
[7.03] Choose the correct simplification of the expression (2x7y)2(y5)3.
4x7y10
4x9y10
4x14y16
4x14y17
OpenStudy (oaktree):
You forgot to add the powers on the a.
OpenStudy (oaktree):
OOPS.
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OpenStudy (anonymous):
Ohhhh I see now
OpenStudy (anonymous):
Lol
OpenStudy (oaktree):
Okay. This next one is just like the last one, except it's a problem in a problem. Let's take it step by step.
OpenStudy (anonymous):
Ok
OpenStudy (oaktree):
First, do the power to a powers. \[(2x7y)^2 * (y^5)^3 = (2x7y)(2x7y)*(y^5)(y^5)(y^5)\]
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OpenStudy (oaktree):
Can you simplify that?
OpenStudy (anonymous):
a little confused
OpenStudy (oaktree):
First do the 2x7y part. There's an imaginary exponent of 1 on top of each of them. What's 1+1?
OpenStudy (oaktree):
(wow, I feel stupid)
OpenStudy (anonymous):
lolllll
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OpenStudy (anonymous):
2
OpenStudy (oaktree):
Oh, wait. Is that\[2x7y\]or \[2x^7y\]
OpenStudy (oaktree):
Because there's a significant difference.
OpenStudy (anonymous):
Second option
OpenStudy (oaktree):
OK. Nevermind, then!
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OpenStudy (oaktree):
It's time to learn a shortcut.
OpenStudy (anonymous):
The one where the 7 is higher
OpenStudy (anonymous):
Lol Im ready
OpenStudy (oaktree):
Any time you have a problem of the form\[((some constant)*a^x*b^y)^c\]
OpenStudy (oaktree):
You multiply x and c as well as y and c, but take the constant to the c power. So it's\[(someconstant)^c*a ^{xc}*b^{yc}\]
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OpenStudy (oaktree):
In this case, we have \[(2x^7y)^2\]
OpenStudy (anonymous):
Hmm? What would be the constant
OpenStudy (anonymous):
Oh
OpenStudy (oaktree):
Can you evaluate that? Just multiply the 2 by the exponents and take 2^2.
OpenStudy (oaktree):
And remember it's technically y^1.
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OpenStudy (anonymous):
Ok so that would be 2
OpenStudy (anonymous):
Sorry im a little bit slow with math :c
OpenStudy (anonymous):
oh wait wouldnt that be 14 and 4 @oaktree
OpenStudy (oaktree):
Like \[4x^{14}y^2\]
OpenStudy (anonymous):
Ohh ok that makes a lot more sense
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OpenStudy (oaktree):
:-)
OpenStudy (anonymous):
My question is a little different then this one
OpenStudy (anonymous):
Thank You @Oaktree