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f(x)=5/x^2+sinx How do you find f '(x)?
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is it \[f(x)=\frac{5}{x^2}+\sin(x)\] or \[f(x)=\frac{5}{x^2+\sin(x)}\]?
The first one
ok then take the derivative piece by piece you know the derivative of sine?
cos
ok good how about the derivative of \(\frac{5}{x^2}\)?
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-10x/x4
if you want you can write is as \[5x^{-2}\] and use the power rule
-10x^-3
or you can do what you did, but then make sure to cancel an \(x\) top and bottom, because \[-\frac{10x}{x^4}=-\frac{10}{x^3}\]
same answer either way, and now you are done answer : \[-\frac{10}{x^3}+\cos(x)\]
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Thanks
yw
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