Question

The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?
Which of the following equations is used in the process of solving this problem?

3n^2+ 5 = 116
3n^2+ 3n + 3 = 116
3n^2+ 6n + 5 = 116

Answer 1

Consecutive integers would be represented by x, x+1, x+2
Squaring and summing them would make x^2+(x+1)^2+(x+2)^2=116
foil and combine like terms.

Answer 2

are you sure that is 116 ?

Answer 3

if what is 116??

Answer 4

they are cant be integers

Answer 5

the question is correct

Answer 6

yeah, but the wrong statement. if just findind an equation we can do it, but if want to solving we cant solve it

Answer 7

I trying to find the process that is used to solve it

Answer 8

i meant, can be solved but if just they are real numbers not integer numbrs

Answer 9

None of the equations listed have integer solutions...

Answer 10

if just want to find the equation :
x^2+(x+1)^2+(x+2)^2=116
x^2 + x^2 + 2x + 1 + x^2 + 4x + 4 =116
3x^2 + 6x + 5 = 116 ( it is C)

but if want solve it :
3x^2 + 6x + 5 = 116
3x^2 + 6x + 5 - 116 = 0
3x^2 + 6x - 111 = 0
------------------ : 3
x^2 + 2x - 37 = 0
this can not be fatored, so obviously the roots not integer numbers

Answer 11

in other words, wrong question. heh

Answer 12

that's what I needed to know thx

Answer 13

One of the shortcomings of learning from a canned course: no opportunity to give the teacher a hard time about a badly written question :-)