Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Find x in these 30 - 60 - 90 triangles. https://media.glynlyon.com/g_geo_2012/11/groupi39.gif x = ? It's in the form of sqrt.

OpenStudy (anonymous):

is it trigono ?

OpenStudy (anonymous):

yeah, kinda. It's geometry, but they're using the sin,cos, and tan.

OpenStudy (anonymous):

@tanjung

OpenStudy (anonymous):

it would be a special triangle

OpenStudy (anonymous):

you would write 30 : 60 :90

OpenStudy (anonymous):

then find what is across the 30, 60 , 90

OpenStudy (anonymous):

get me?

OpenStudy (jdoe0001):

http://upload.wikimedia.org/wikipedia/commons/4/45/30-60-90_triangle.jpg 30-60-90 rule notice the ratios

OpenStudy (anonymous):

30:60:90 x: 7:y 1:square root 3: 2

OpenStudy (jdoe0001):

based on the ratios on the 30-60-90 rule \(\huge 7 = x\sqrt{3}\) then just solve for "x" :)

OpenStudy (anonymous):

No, I don't get it..

OpenStudy (anonymous):

This is how they want it:

OpenStudy (jdoe0001):

hmm, well $$ 7 = x\sqrt{3} \implies x = \frac{7}{\sqrt{3}}\\ \text{now in simplified form}\\ \implies \cfrac{7}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} \implies \cfrac{7\sqrt{3}}{(\sqrt{3})^2}\\ \cfrac{7\sqrt{3}}{3} $$

OpenStudy (anonymous):

Thanks @jdoe0001

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!