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Mathematics 18 Online
OpenStudy (anonymous):

determine the roots algebraically by factoring. \[4x^4-4x^3-51x^2+106x-40\]

OpenStudy (mertsj):

Do you know synthetic division?

OpenStudy (whpalmer4):

Thanks to the rational root theorem, we have some candidates to try for roots. Factor -40, and 4 (the constant term and the coefficient of the leading term respectively). Any rational roots will be found on a list made up of all the different factors of the constant term over all the different factors of the leading term. There are quite a few of them here! You can test a root candidate by plugging it into the polynomial. If the polynomial evaluates to 0, that candidate is a root. With each root \(r_n\) you find, you can divide the polynomial by \((x-r_n)\) to get a simpler polynomial with the same roots as the roots you have yet to find in the original.

OpenStudy (anonymous):

@Mertsj yes i do

OpenStudy (mertsj):

The possible shelf numbers are the factors of the constant term, which is 40, divided by the coefficient of the leading term, which is 4.

OpenStudy (mertsj):

So here are the possibilities: \[\frac{\pm 1,\pm 2,pmn4,\pm 5, \pm8, \pm10, \pm20, \pm40}{\pm 1, \pm 2, \pm4}\]

OpenStudy (mertsj):

Test those until you find one which gives a remainder of 0.

OpenStudy (whpalmer4):

we could make this a probability question: what is the probability that any root candidate, randomly selected, is actually a root of P(x)? :-)

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