Question

Please don't tell my the answer just lead me into the right direction.
Alert you have to be a super genius to solve.

Answer 1

x,y,z are the reals that satisfy
\[2x^{2}y ^{2}+x ^{2}+2y ^{2}=87\]
\[2y ^{2}z ^{2} + y ^{2} +z ^{2} = 82\]
\[2z ^{2}x ^{2} + 2z ^{2}+x ^{2} = 119\]

Answer 2

This is what Open Study is made for. To help people understand what they're doing. ;)

Answer 3

Yeah, but I really don't want people to explain than tell me the answer I just want that to guide me and explain how don't tell me the answer.

Answer 4

Thank you for helping me with my mathematics though :)

Answer 5

If people are just telling you the answer, then report them.(That's how I got a warning) They're not allowed to tell you the answer (Even though so many people are doing it), without showing some work/proof.

According to the Code of Conduct:
"Don't devalue the question/answer process!

Don't provide someone with just the answer - explain the process, and help guide them through understanding the problem.
Don't just provide the answer to a problem when someone else is in the middle of helping! But if you want to help, by all means, join in!"

Answer 6

Thanks but can you help me with this problem in simple terms everyone else cant't explain. For my class.

Answer 7

I can't help you, I have to go to sleep.
But I'm sure someone will help you within a few minutes. ;)

Answer 8

Alright but thanks for telling me instead of ditching out good night.

Answer 9

Wait that's not the whole question

Answer 10

Determine(\[xyz)^{2}\]

Answer 11

That"s what it says at the end sorry for the inconvenience .

Answer 12

Would you believe there are 16 solutions? You get 2 different values for \((x y z)^2\)

Now, how to get them without computer assistance...hmm...

Answer 13

All I know is that the solutions have to be integers between 0 & 999

Answer 14

Well the solution but I have no idea how to do

Answer 15

Hmm. That doesn't square with what I see.

Answer 16

Wait, when you say "the solutions" are you referring to the values of \(x,y,z\) or \((xyz)^2\)? The latter meet that restriction, the former do not.

Answer 17

I thought that we need to use the method of elimination or substitution but that never worked. Oh I don't understand. :(

Answer 18

I guess the 0 < solution < 999 eliminates half of the solutions I see (the complex ones).

Answer 19

These solutions are all reals not like infinity or something like that.

Answer 20

I mean the values for x y z and then to figure it out.

Answer 21

No wait I barely understand algebra don't confuse me please.

Answer 22

What class is this for?

Answer 23

Nope I'll never give up and this class just some online college work I guess.

Answer 24

maybe high school.

Answer 25

you could probably start by eliminating x^2 by multiplying -1 to the last equation, so you'd have +x^2 in the first equation and -x^2 in the last equation

Answer 26

hmm thanks for the input so using the elimination method.

Answer 27

yep

Answer 28

how so can you give me a pictorial representation

Answer 29

you like write it

Answer 30

because how who you be able to use the elimination method when you aren't able to match the variables together.

Answer 31

Using the first equation and last equation of course.