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OpenStudy (anonymous):
OpenStudy (anonymous):
how can i write the two expression written in the last for the solution of the differential equation?
OpenStudy (anonymous):
You can multiply and divide the solution by \[\sqrt{c _{1^{2}} + c _{2^{2}}}\]
Taking the solution as resembling the expansion of \[\sin(A+B)\] or \[\cos (A+B)\] we can reduce into the two forms.
OpenStudy (anonymous):
And the equation is of a simple harmonic oscillator.
OpenStudy (anonymous):
yes, it is of simple harmonic oscilator only
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OpenStudy (anonymous):
could you please elaborate a bit more...
OpenStudy (anonymous):
yeah, it may take some time.
OpenStudy (anonymous):
u have all the time :)
OpenStudy (anonymous):
i think i found the solution.
if i take c1 = A sin (phi)
and c2 = A cos (phi)
then i am geting the solution
OpenStudy (anonymous):
yeah, you can reverse sin and cos for getting the other one.
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OpenStudy (anonymous):
I was saying the same thing. Now you get \[A ^{2} = c _{1^{2} }+c _{2^{2}}\]