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Mathematics 9 Online
OpenStudy (anonymous):

Arianna kicks a soccer ball off the ground and into the air with an initial velocity of 42 feet per second. Assume the starting height of the ball is 0 feet. Approximately what maximum height does the soccer ball reach? 1.3 ft 2.6 ft 26.0 ft 27.6 ft

OpenStudy (anonymous):

s = ut+1/2at^2 where u = 42 and a=-9.81 Now, find the maximum value of s

OpenStudy (anonymous):

I assume acceleration due to gravity is 9.81m/s^2

OpenStudy (anonymous):

wouldn't s=0?

OpenStudy (anonymous):

yes s=0 initially.... but it increases as it is thrown up until it reaches the maximum height

OpenStudy (anonymous):

u can use calculus to find maximum value of s or use completing square form

OpenStudy (anonymous):

ummm......i'm still lost, sorry.....

OpenStudy (anonymous):

what value of acceleration due to gravity is given?

OpenStudy (anonymous):

42?

OpenStudy (anonymous):

looks like I made a mistake

OpenStudy (anonymous):

acceleration due to gravity in terms of feet per second square is 32.2 feet per second square

OpenStudy (anonymous):

So, s= 42t - 16.1t^2

OpenStudy (anonymous):

Now find maximum value of s

OpenStudy (souvik):

you can use this... \[v ^{2}=u ^{2}+2g h\] here the initial velocity u =42 feet per second final velocity at maximum height v=0 g=-32 feet per second per second find h(height)

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