Arianna kicks a soccer ball off the ground and into the air with an initial velocity of 42 feet per second. Assume the starting height of the ball is 0 feet. Approximately what maximum height does the soccer ball reach? 1.3 ft 2.6 ft 26.0 ft 27.6 ft
s = ut+1/2at^2 where u = 42 and a=-9.81 Now, find the maximum value of s
I assume acceleration due to gravity is 9.81m/s^2
wouldn't s=0?
yes s=0 initially.... but it increases as it is thrown up until it reaches the maximum height
u can use calculus to find maximum value of s or use completing square form
ummm......i'm still lost, sorry.....
what value of acceleration due to gravity is given?
42?
looks like I made a mistake
acceleration due to gravity in terms of feet per second square is 32.2 feet per second square
So, s= 42t - 16.1t^2
Now find maximum value of s
you can use this... \[v ^{2}=u ^{2}+2g h\] here the initial velocity u =42 feet per second final velocity at maximum height v=0 g=-32 feet per second per second find h(height)
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