Question

Position vs Time graph of an object thrown directly upward

Answer 1

is it a parabola

Answer 2

Forgot ur axes :P y:velocity x:time
position vs time? Yup, I think it's a parabola too since the acceleration due gravity (displacement vs time graph would be a parabola)

Answer 3

\[y = u \times t - 1/2 \times a \times t ^{2}\]
so its a parabola as above
y-position co-ordinate
u-initial velocity
a-acceleration
t-time

Answer 4

I'm with both chenping and koushik_ksv.

\(\boldsymbol koushik\_ksv\ shows\ the\ equation.\) It's immediately above this response.
The "\(y=\)" part starts the function,
the "\(u\times t\)" part is an addition (raises the \(y\) by its amount),
and the \(-\frac{1}{2}\times a\times t^2\) is an upside-down parabola. Parabola because of the \(t^2\) multiplied by a constant (\(\frac{1}{2} \times a\)), and upside-down because of the negative.

\(\boldsymbol You\ can\ think\ of\ it\ conceptually\ like\ this.\)

You start at the origin, saying that the object's not "up" at all and no time has passed since the throwing.

1. As time passes, the ball will first go up. That is the initial velocity of the object that you gave it wit the throw.

2. Soon, though, the acceleration from gravity has slowed the object. This means that the object can't go as far in that time. As time passes, the acceleration has been taking its toll on velocity for longer. The velocity becomes less, and less, and less. Each passing second, say, the object can only rise a smaller, and smaller, and smaller distance.

3. Eventually, the acceleration from gravity on the object takes away ALL of it's velocity. At this point, the object's ascent stops.

4. Now acceleration from gravity keeps on doing its thing. The object's velocity starts going downwards as time goes on.

5. In a similar fashion to how the objects slowed to the top, the object will gain speed as it falls. This is, again, because the acceleration continues to make the velocity get greater downward. In each passing second the velocity will get greater, and greater, and greater downward. So in each passing second the falling object will go farther, and farther, and farther.