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Period for cot4x? Is it pi/4?
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If I remember correctly, the period of a trig function is equal to 2pi/frequency, which in this case would be: \[T=2\pi / 4 = \pi/2\]
But the normal frequency of cot is pi, isn't it?
Yes, you're right, I'm sorry, I was thinking about sine and cosine. Yes, it would be pi/4.
Now take a look at the graph of cot(4x) The lines, they cross at pi/8 and pi/16, no?
They don't cross through pi/4.
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There are vertical asymptotes, and the distance between them is the equal to the period. I graphed it, and it looks like the asymptotes are pi/4 apart.
OH I thought that pi/4 was where they intersected the graph!
Period of cot 4x is pi/4
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