Two forces with magnitudes of 200 and 100 pounds act on an object at angles of 60° and 170° respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer.
You can decompose to x and y components by \[x = r \cos \theta\]\[y = r \sin\theta\]
Where r is what? the 200/100 and theta is 60 and 170?
R is magnitude of vector, so 200 or 100 (you do this procedure twice)
Theta is the angle of course
ok, so x=200cos60 and y=100cos170 and what would this be finding? the terminal point of the vector?
Then sum x components to get x component of new vector, and sum y components to get y component of new vector
you can easily see that the angle between the forces is 170-60 =110 degrees. You have the magnitude of the two forces and the angle between them.. now use this formula to get the resultant, |dw:1372962726835:dw| and for direction, find the angle the Resultant R makes with the first force using, |dw:1372962805711:dw| Then you can say that the resultant makes an angle
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