Question

Can anyone walk me through the steps of this quadratic equation, tell me what the discriminant is and how to check it for its truth value in the end?

a^2 - 6a + 9 = 0

Answer 1

http://www.bbc.co.uk/bitesize/higher/maths/algebra/quadratic_theory/revision/4/

that is where I learnt it from

Answer 2

Thank you for the information, looking it over now!

Answer 3

great. So in your equation a = 1, b = -6 and c = 9

its a shame your variable is a, and the variable in the quadratic equation is also called a. makes it abit confusing

Answer 4

I know, the quadratic formulas are also difficult for me to write.

Answer 5

The discriminant is \[ 6^2 - 4(1)9=36-36=0\]
So your quadratic is a perfect square
\[ a^2 -6 x + 9= (a-3)^2=0\]
So the two roots are equal and each one of them is equal to 3

Answer 6

I should have put \( (-6)^2 \) above.

Answer 7

Hello eliassaab, thank you for helping me. are you stating that the last part of the equation should be written a&2 (-6) + 9 = (a-3)^2 = 0

Answer 8

When computing the discriminant
\[
b^2 - 4 a c = (-6)^2 - 4(1) 9 = 36-36=0

\]

Answer 9

It does not matter since \[(-6)^2 = 6^2 =36\]

Answer 10

I was just confirming what you wrote. Thank you!

Answer 11

YW

Answer 12

Yep, when the discriminant \(\large D = 0\) , you result in one real zero (answer) with a multiplicity of 2.

Answer 13

Thanks Jhannybean. I am trying to write the answer step by step.

Answer 14

Good luck! :)

And no problem.

Answer 15

Thank you!