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if x=m^3 and y=2n^2, write the following in terms of m and r. 3x^2y
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I think you meant to say "in terms of m and n" (not m and r)
am I correct with that assumption?
the paper says m and r but I thinks its m and n
yeah I think it's m and n too because r is nowhere to be found
x=m^3 x^2=(m^3)^2 ... square both sides x^2=m^(3*2) x^2=m^6
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3x^2y 3m^6y ... replace x^2 with m^6 (since x^2 = m^6, found earlier) 3m^6*2n^2 ...replace y with 2n^2 (because it's given that y = 2n^2) 3*2m^6n^2 6m^6n^2 so this means that 3x^2y = 6m^6n^2 when x = m^3 and y = 2n^2
ohh it makes much more sense, thank you so much!
you're welcome
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