Question

(2x²-1x) - (3x²+2) (these are numerators)

Answer 1

denominator is x³

it's just the last step in simplifying a radical equation

Answer 2

expression*

Answer 3

\[\huge\frac{(2x^2-x)-(3x^2+2)}{x^3}\]

Answer 4

ok I'm awful with the equation thing, but it's 2x^2 - x over x³ minus -1x+2 over x³

Answer 5

ok, the same mine, friend. since they have the same denominator, you can combine like this.but what do you want me to do?

Answer 6

\[\large \cfrac{(2x^2-x)-(3x^2+2)}{x^3}\] distribute the negative to the \(\large 3x^2+2\) first.
\[\large \cfrac{2x^2-x-3x^2-2}{x^3}\] Simplify the numerator. \[\large \cfrac{(2x^2-3x^2)-(x+2)}{x^2}\] What do you ge when you simplify the numerator?

Answer 7

It's probably easier to explain if you just combine like terms then factor.

Answer 8

That's for the asker to do, not me.