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m^x+y / m^x-y
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Is it \[\large\cfrac{m^{x+y}}{m^{x-y}}\]
yeah
This would result in \[\large m^{(x+y)-(x-y)}\] Can you evaluate this?
sorry im abit confused how to get m(x+y)-(x-Y)
ohh nevermind I got it !:)
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Awesome :D
What did you get as your answer? :)
im not sure if this right but I distributed the m and got mx+my-mx-my
just distribute the negative sign to (x-y)
m(x+y)-x+y ? is that right
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\[\huge m^{(x+y)-(x-y)} = m^{x+y-x+y}\]
Yes you are right :)
Now simplify the exponent and combine like-terms :P
mx^2y^2?
Close! \[\huge m^{2y}\]
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The x's canceleachother out and you're left with \(\large m^{1y+1y} = m^{2y}\)
ohh oops I thought both the x's were positive :P Thank you soso much for your help :D
No problem :D
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