Question

I am having trouble with this....I have done it twice and am getting different answers...help

Answer 1

If 3x + (1/3)x = 3.....find the value of 9x^2 + 1/9x^2

Answer 2

oops...the last part of that is (9x^2 + 1)/(9x^2)

Answer 3

what do you get when you solve 3x + (1/3)x = 3 for x

Answer 4

I got 9/4 = x

Answer 5

that's not correct

Answer 6

let me do it again...
3x + 1/3x = 3
3/3x + 1/3x = 3
4/3x = 3
x = 3 * 3/4 = 9/4
what am I doing wrong ?

Answer 7

3x is NOT 3/3x

Answer 8

3x is (9/3)x

Answer 9

oh....9/3x...
9/3x + 1/3x = 3
10/3x = 3
x = 3*3/10 = 9/10

Answer 10

should I make that a decimal for the other problem or leave it as a fraction ?

Answer 11

leave it as a fraction

Answer 12

now plug it into (9x^2 + 1)/(9x^2) and simplify

Answer 13

(9x^2 + 1)/(9x^2)
(9(9/10*9/10) + 1)/ (9(9/10 *9/10)
right so far ?

Answer 14

yep

Answer 15

you replaced every x with 9/10 and expanded (9/10)^2 into (9/10*9/10)

Answer 16

(9(81/100) + 1)/(9(81/100)
((729/100) + 1) / (729/100)
(729/100 + 100/100) / (729/100)
(829/100) / (729/100)
829/100 * 100/729
829/729......is that correct ?

Answer 17

very nice work

Answer 18

It all started with that stupid mess up at the very beginning.....thanks for setting me straight

Answer 19

yw, glad to be of help

Answer 20

I will close this now.....jim, your the best :)

Answer 21

thanks lol