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\[\left| \frac{ 1 }{ 2 } -\frac{ \sqrt{3} }{ 2 }i\right| = 1?\]
formula of absolute value of complex number is: \[ \left| r \right| = \left| a + bi \right| =\sqrt{a^{2} + b^{2}} = \sqrt{(\frac{ 1 }{ 2 })^{2} + (\frac{\sqrt{3} }{ 2 })^{2}} = \sqrt{\frac{ 1 }{ 4 } + \frac{ 3 }{ 4 }} = \sqrt{1} = 1\] yes, 1 is correct answer
its magnitude is \[\sqrt{(1/2)^{2}+(-\sqrt{3}/2)^{2}}\]=1
:O that was mind blowing :/ ... thanks!
one tiny mistake, sqrt(3)/2 in my equation misses a minus. it doesn't change anything, but still;) thx souvik @souvik
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