Question

Write an equation for the parabola in standard form with (3,2) and (4,0)

Answer 1

Which of these is the Vertex and the Focus?

Answer 2

vertex 4,0 focus 3,2

Answer 3

Okay give me a sec

Answer 4

just sent the graph

Answer 5

apply the definition of parabola.

Answer 6

is standard form
ax^2+bx+c
or vertex form
a(x-k)^2=(y-c)

Answer 7

since your V and F ... if thats how they are defined ... are not on the same x or y axis, your parabola is skewed

Answer 8

oh, vertex is 4,0 and a point on it is 3,2

Answer 9

you have the vertex, but not the focus
what you have is another point on the graph
you know it looks like
\[y=a(x-4)^2\] because you only have one zero at \(x=4\)
solve for \(a\) via
\[2=a(3-4)^2\]

Answer 10

the axis of this parabola is not parallel to the x-axis or the y-axis.

Answer 11

because if \((3,2)\) i on the graph, that means if \(x=3\) then \(y=2\)

Answer 12

amistre is gonna be 100 soon

Answer 13

only if i keep kicking satellite off the OS ;)

Answer 14

i think you will find that \(a=2\) and so the equation is for
\[y=2(x-4)^2\] or whatever you get when you multiply that out

Answer 15

sateliite deserves the 100 spot, since he is simply smarter then me

Answer 16

is that why i keep getting suspended? i thought it was for spam

Answer 17

not true, just have more time on my hands
now that i quit ...

Answer 18

i have more time on my hands now that i got an office job ...

Answer 19

vertex-4,0 and focus 3,2.
the axis of the parabola is at some inclination to the x axis.
it is not like y=ax^2+bx+c

Answer 20

yeah if thats the given data, then it would get complicated i think
interesting to see how the equation looks for a skewed parabola...

Answer 21

equation may have sin and cos ?

Answer 22

if those are the focus and vertex, we could move this so the vertex is at the origin: V = 0,0, F = -1,2, and determine the slope of the line for the tan(a)

then rotate it about using X = x cos(a) ... etc

Answer 23

the distance between them is sqrt(5)

so an equivalent parabola with vertex 0,0 and focus 0,sqrt(5) could be constructed then rotated back and shifted again

Answer 24

I'm thinking it's