I Really need help for this problem!!!! See attachments
do you know how to write the slope-intercept form of that line? (i mean the one with y = mx + b)
no sorry i dont know
hmm well.. do you know the two-point formula to find the equation of a line?
no and im really stuck on this problem its taken my hours :(
okay...the two point formula of a line is \[\large y - y_1 = \frac{y_2 - y_1}{x_2 - x_1} (x - x_1)\] your points are (0,3) and (2,-3) so x1 = 0, y1 = 3, x2 = 2, y2 = -3 substitute those into the equation i wrote then tell me what you have
i did that i have gotten it wrong because of the shadowed part
let me do the equation on paper one minute
sure. anyway...the shadowed part doesn't matter for now. first step is to make it into an equality to make it easier
so how do i put an input for the y int he begining
the y and x with no subscripts are variables
like the ones in y = mx + b
ok so just leave it as it is?
yes
ok so is it y-3=-6/2(x-0)
now simplify it
y-3=-3(x-0)
right. further simplification is y - 3 = -3x now turn that into the y = mx + b form
how to put an input into mx?
mx is just the term that has the x
in this case mx is -3x
what would y be
again, y is a variable
b is the constant
y=-3x+-3
or y=-3x+y-3
it's y = -3x - 3 <--your first answer
anyway, we're done with 3/4 of the problem now. the only thing left is to change that equal sign into an inequality sign
which do yo think is the proper inequality sign? remember: your graph is shaded to the left, and has shaded dots on the points
>
nope. remember, in the number line, the left side is negative and the right side is positive and shaded circles means equality
greater than or equal too?
it's actually less than or equal to...because like i said a while ago, the left is negative..in short less than... remember that you're supposed to look at the shade, not the line
the line is greater than the shaded region...but the shaded region is less than that line. make sense?
ohhh so ho would the equation look like
\[y\le -3x - 3\]
i have one more question
go ahead
would there be a website online that can calculate this or convert in some sort
www.wolframalpha.com
thank you very much
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