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Mathematics 7 Online
OpenStudy (anonymous):

Part 1: Find the polynomial f(x) that has the roots of –2, 5 of multiplicity 2. (4 points) Part 2: Explain how you would verify the zeros of f(x). (4 points)

OpenStudy (anonymous):

the root 5 has multiplicity 2 that means the factor is \((x-5)^2\)

OpenStudy (anonymous):

close, but the one you wrote has 3 zeros: 2, 5, and -5

OpenStudy (anonymous):

"multiplicity 2" means that the factor has a square that is the "2"

OpenStudy (anonymous):

\[(x+2)(x-5)^2\] is what it means i this case

OpenStudy (anonymous):

no

OpenStudy (anonymous):

it says 5 of multiplicity 2

OpenStudy (anonymous):

Ok, so after foiling I get my answer

OpenStudy (anonymous):

if you mean "multiply" then yes, there is no such mathematical operation as "foil" you have to multiply \[(x+2)(x-5)(x-5)\] if you want to write it in standard form

OpenStudy (anonymous):

me, i would leave it in factored form, but that might not be what your teacher had in mind they tend to be picky about such thigs

OpenStudy (anonymous):

ok, at the risk of repeating myself, what you need is to "multiply" if you want to call it "foil" ok, but there is no "first outer inner last" when multiplying \[(x^2-3x-10)(x-5)\]

OpenStudy (anonymous):

btw i noticed that again you changed \(x-5\) in to \(x+5\) it is \[(x+2)(x-5)(x-5)\]

OpenStudy (anonymous):

absolutely

OpenStudy (anonymous):

no problem, it is not your fault, i am sure that is what your math teacher called it

OpenStudy (anonymous):

yw

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