Part 1: Find the polynomial f(x) that has the roots of –2, 5 of multiplicity 2. (4 points) Part 2: Explain how you would verify the zeros of f(x). (4 points)
the root 5 has multiplicity 2 that means the factor is \((x-5)^2\)
close, but the one you wrote has 3 zeros: 2, 5, and -5
"multiplicity 2" means that the factor has a square that is the "2"
\[(x+2)(x-5)^2\] is what it means i this case
no
it says 5 of multiplicity 2
Ok, so after foiling I get my answer
if you mean "multiply" then yes, there is no such mathematical operation as "foil" you have to multiply \[(x+2)(x-5)(x-5)\] if you want to write it in standard form
me, i would leave it in factored form, but that might not be what your teacher had in mind they tend to be picky about such thigs
ok, at the risk of repeating myself, what you need is to "multiply" if you want to call it "foil" ok, but there is no "first outer inner last" when multiplying \[(x^2-3x-10)(x-5)\]
btw i noticed that again you changed \(x-5\) in to \(x+5\) it is \[(x+2)(x-5)(x-5)\]
absolutely
no problem, it is not your fault, i am sure that is what your math teacher called it
yw
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