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Solve 2^x + 3 = 7
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Easy, get everything to one side
\[2^x=4\] \[2^x=2^2\] x=2 :)
\[2^{x+3} = 7\]
Switch it to logs
(x+3)log2 = 7, right?
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\[\log_{2} 7=x+3\] I think..
Hmm its more like this \[(x+3)\log2= \log7\] @Luigi0210
yea luigi's got it
@celecity sorry about that, but did you get it?
(x+3)ln2=ln7 \[\div \ln7\] x+3=2.807354922 -3 -3 x=-0.192645078 x=-0.19
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Huh, good job Sorry about the confusion earlier
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