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Mathematics 12 Online
OpenStudy (anonymous):

Solve 2^x + 3 = 7

OpenStudy (luigi0210):

Easy, get everything to one side

OpenStudy (luigi0210):

\[2^x=4\] \[2^x=2^2\] x=2 :)

OpenStudy (anonymous):

\[2^{x+3} = 7\]

OpenStudy (luigi0210):

Switch it to logs

OpenStudy (anonymous):

(x+3)log2 = 7, right?

OpenStudy (luigi0210):

\[\log_{2} 7=x+3\] I think..

OpenStudy (anonymous):

Hmm its more like this \[(x+3)\log2= \log7\] @Luigi0210

OpenStudy (anonymous):

yea luigi's got it

OpenStudy (luigi0210):

@celecity sorry about that, but did you get it?

OpenStudy (anonymous):

(x+3)ln2=ln7 \[\div \ln7\] x+3=2.807354922 -3 -3 x=-0.192645078 x=-0.19

OpenStudy (luigi0210):

Huh, good job Sorry about the confusion earlier

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