Question

((3^n)^4)((9)^(5n-2))

Answer 1

so,
\(\large (3^n)^4 \times 9^{5n-2}\)
yo need to simplify this?

Answer 2

yes

Answer 3

9 can be written as ?
\(\large 9=3^{??}\)

Answer 4

for the 1st term, you can use the property that
\((a^b)^c= a^{bc}\)
so,
\((3^n)^4=...?\)

Answer 5

3^4n?

Answer 6

3^(4n) x 9^(5n-2) ?
is it necessary if i multiply 3 and 9? and add their exponents?

Answer 7

@hartnn

Answer 8

oh... its not
so the final answer is
3^(4n) 9^(5n-2)
thanks!

Answer 9

is it necessary if i multiply 3 and 9? and add their exponents? <---incorrect
3^(4n) is correct
now, \(9= 3^{??}\)

Answer 10

9 = 3^2

Answer 11

3^(10n-4)

Answer 12

3^(6n-4)?

Answer 13

yes, \(\large 9^{5n-2} = 3^{2 [5n-2]} = 3^{10n-4} \)
got this ?
now you can compare and equate the exponents of 3 :)

Answer 14

on left its 4n
on right its
10n-4
so, solve for 'n' in
4n = 10n-4
n=...?

Answer 15

2/3

Answer 16

correct! :)

Answer 17

oh wait!
you need not solve it, just simplify :P

Answer 18

so
= 3^(8/3) - 3^(8/3)
=0

Answer 19

so,
\(\large 3^{4n} 3^{10n-4} = 3^ {4n+10n-4}= 3^{14n-4}\)
thats simplified...