I need help Really bad please help!!! see attachments
ok, given 2 points can you first find the equation of the line ?
3/5
did u get that as slope of line ? are you sure its 3/5 and not -3/5 ?
y=mx+b?
yes i think it is right:)
Heres the equation for a line given two intercepts. Given the intercepts (a,0) and (0,b) \[x/a + y/b = 1\]
yes, y=mx+b is correct form good, you found m = 3/5 now find 'b' by plugging in any one point, say (0,-3) so, put x=0, y=-3 and find 'b' :)
ok so 3/5 is m
yes.
y-3/5+0
3/5+0-3
what was that ? when you plug in y=-3, x=0 in y=mx+b you get -3 = 0+b so, b= -3 got it ?
ohhh
yes, so you equation of line becomes y=(3/5)x -3 clear till here ?
yes and also is there a greater than or equal to in this equation?
yes, one last step is remaining since it is an inequality, we need to find whether \(y \ge (3/5)x-3\) or \(y \le (3/5)x-3\) do you know how to find ?
yes sir
i think it is the second one
how ?
because of the shaded part
but why not the first one ?
but thats all i know because of the shaded part i dont know fully why?
i think because of the shaded part
ok, let us test a point, which is IN THE SHADED region the easiest one will be the origin (0,0) does 0,0 satisfy 1st equation or 2nd equation ? can you test ?
nope
i dont think it could satisfy
how would i test it
just plug in x= 0, y= 0 in both the equations, and see which relation is true. like if i had to test 0,0 for y > 4x-18 i would plug in x=0, y=0 to get 0 > 0-18 , that is 0 > -18 which IS TRUE got this ?
yes kind of
0 is not greater than 18
so, what about \(y \ge (3/5)x-3\) x=0, y= 0
oh sorry 0 is greater than -18
yes thats true
so now i think its the first one lol
yes, it IS the 1st one :)
thank you
i might have more questions if you see a post of mine can please help me thank you! :D
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