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Mathematics 18 Online
OpenStudy (mikezack123):

Keira created color panels for a wall using a mix of only red and blue paints. She plotted the quantities of red and blue paints used for each mix and connected them using a line segment as shown in the graph below.

OpenStudy (mikezack123):

Which statement best describes the domain of the function represented in the graph? 3 ≤ x ≤ 12 or x is between 3 and 12, inclusive 3 ≤ x ≤ 7 or x is between 3 and 7, inclusive 2 ≤ x ≤ 12 or x is between 2 and 12, inclusive 2 ≤ x ≤ 7 or x is between 2 and 7, inclusive

OpenStudy (mikezack123):

@Callisto @matricked @kropot72 @harsimran_hs4 Please help

OpenStudy (harsimran_hs4):

@MikeZack123 the link is not working for me....maybe you could post a screenshot

OpenStudy (anonymous):

@MikeZack123 link is having error

OpenStudy (mikezack123):

OpenStudy (mikezack123):

here you go :)

OpenStudy (mikezack123):

@Callisto @matricked @kropot72 @harsimran_hs4 i posted the image

OpenStudy (whpalmer4):

Well, what's value of x at the left end of the line? What is the value of x at the right end of the line?

OpenStudy (mikezack123):

3 at the left 7 at the right...

OpenStudy (harsimran_hs4):

the b option should be correct method of determining the domain is you drop a line perpendicular from the end points of the graph, and the point at which it cuts the x axis gives you the domain

OpenStudy (whpalmer4):

then 3 <= x <= 7 is your domain.

OpenStudy (whpalmer4):

all the points on the line fall in that range.

OpenStudy (mikezack123):

Oh okay thanks! :) Thank you both :)

OpenStudy (whpalmer4):

uh, I shouldn't say "range" I suppose :-)

OpenStudy (mikezack123):

lol @whpalmer4 i get it! XD

OpenStudy (whpalmer4):

what is the range of this function?

OpenStudy (harsimran_hs4):

also , |dw:1373088698809:dw| if there is a uncolored circle then it means don`t include the point, else include it

OpenStudy (mikezack123):

between 2 and 12 @whpalmer4 ... ?

OpenStudy (whpalmer4):

yes! and you'll notice the dastardly problem author threw that in as an answer choice to trap the unwary...

OpenStudy (mikezack123):

lol thanks again :) @whpalmer4

OpenStudy (mikezack123):

and thanks @harsimran_hs4 :)

OpenStudy (harsimran_hs4):

Welcome :)

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