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Mathematics 56 Online
OpenStudy (anonymous):

hi, how can i solve lim((sqrt(5+h)-sqrt(5))/h) where h->0

OpenStudy (callisto):

\[lim_{h\rightarrow 0}\frac{\sqrt{5+h}-\sqrt5}{h}\]\[=lim_{h\rightarrow 0}\frac{\sqrt{5+h}-\sqrt5}{h} \times \frac{\sqrt{5+h}+\sqrt5}{\sqrt{5+h}+\sqrt5}\]\[=lim_{h\rightarrow 0}\frac{(\sqrt{5+h}-\sqrt5)(\sqrt{5+h}+\sqrt5)}{h(\sqrt{5+h}+\sqrt5)}\]Can you simplify it?

OpenStudy (anonymous):

only i little, \[\lim_{h \rightarrow 0} \frac{ h }{ h \sqrt{5+h} +h \sqrt{5}}\]

OpenStudy (callisto):

Don't need to expand the numerator, since you can cancel a common factor.

OpenStudy (anonymous):

yep u right \[\lim_{h \rightarrow 0} \frac{ 1 }{ \sqrt{5+h} +\sqrt{5} }\]

OpenStudy (callisto):

Now, evaluate the limit.

OpenStudy (anonymous):

\[\lim_{h \rightarrow 0} \frac{ 1 }{ 2\sqrt{5} } = \frac{ 1 }{ 2\sqrt{5} }\] thanks a lot calisto !

OpenStudy (callisto):

Welcome :)

OpenStudy (callisto):

Multiplying a conjugate is the key to solve this question :)

OpenStudy (anonymous):

jeah ive got blocked, thinking in silly ways ;)

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