cal help pl ...
\[\int\limits \frac{ dx }{(2+cosx) }\]
@terenzreignz @UnkleRhaukus @texaschic101
@whpalmer4
Substitute \[\tan (x/2) = t\] Then \[\cos x = 1 -t ^{2}/1+t ^{2}\] \[dx = 2 dt/1+t ^{2}\] You will end up with a quadratic. Then integrate.
weres how did u assume that tanx/2 ....
You have the complete solution now.
yaa but i have not yet got clicked about tanx/2
2 + cosx = 1 + 2cos^2 (x/2) 1/(1+ 2cos^2 (x/2)) = sec^2 (x/2) / (sec^2 (x/2) + 2) = sec^2 (x/2) / (tan^2 (x/2) + 3) now tan(x/2) = t seems more logical
u=tan(x/2) was just a substitution to make things easy....in the end you'll see u has been replaced by tan(x/2)..you don't wanna do that, no problem just don't put u=tan(x/2)..it won't make any difference..it'll just make things look messy
thanks ,.... guys ...
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