Question

A garden plot is to contain 240 sq. ft. If its length is to be 3 times its width,what should its dimensions be?

Answer 1

help sir :)

Answer 2

if you call the width \(w\) then the length would be \(3w\) making the area \[w\times 3w=3w^2\]
since you know it is 240 set
\[3w^2=240\] and solve for \(w\) om twp steps

Answer 3

in two steps

Answer 4

divide by 3
take the square root

Answer 5

it should be two answers

Answer 6

what are the dimensions

Answer 7

we are solving for one variable, namely \(w\) which is the width

Answer 8

if you know \(w\) then the length is three time that

Answer 9

the answer should be 4 square root of 5 and 12 square root of 5

Answer 10

yes it should

Answer 11

is it clear how to get that answer?

Answer 12

how to get 12 square root of 5?

Answer 13

multiply \(4\sqrt{5}\) by \(3\)

Answer 14

the width is \(4\sqrt{5}\) and you are told that the length is three times the width, so if you know the width, multiply it by 3 to get the length

Answer 15

why?

Answer 16

is it clear why the width is \(4\sqrt 5\) ?

Answer 17

yes,but how did you get 12 square root of 5?

Answer 18

\[\large \text{" its length is to be 3 times its width"}\]

Answer 19

so as i wrote above, if you know the width, you know the length. multiply it by three

Answer 20

oh I get it, thank you sir, I thought its complicated

Answer 21

sir I have a question

Answer 22

Determine the diagonal of the rectangle inscribed in an isosceles right triangle,if the upper two vertices of the rectangle lie at the midpoints of the legs of the triangle