Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

-x^2 + 4X + 5 >0

OpenStudy (amistre64):

might want to multiply both sides by -1, and see if you can factor it

OpenStudy (anonymous):

x^2 -4X + 5 < 0 how do i find x? can you show me the way? the primary language of my country is not english so i don't understand words like factor

OpenStudy (anonymous):

-x^2 + 4X + 5 >0 i.e. x^2 -4X - 5 >0 i.e. x^2 -5X+x - 5 >0 i.e. x(x -5)+1(x - 5) >0 i.e. (x +1)(x - 5) >0 thus either (x +1)>0 or (x - 5) >0 i.e x>-1 or x>5

OpenStudy (amistre64):

-x^2 + 4X + 5 >0 x^2 - 4X - 5 < 0 we want factors of -5 that add up to -4

OpenStudy (amistre64):

dp, flip you inequality sign when negating

OpenStudy (amistre64):

ideally, just find the roots or zeros of the function, and test the vertex to see if its positive or negtaive

OpenStudy (anonymous):

so wait it cant be x>-1 or x>5 it can be either x<-1 or x>5 or it can also be x>-1 and x<5 (or if you want: -1<x<5) which one is it?

OpenStudy (anonymous):

The ans can be written as -1<x>5

OpenStudy (anonymous):

so it is x<-1 or x>5?

OpenStudy (anonymous):

No, it is -1<x or x>5

OpenStudy (anonymous):

Combining both we can write it together as-1<x>5

OpenStudy (anonymous):

dude -1<x or x>5 is just like x>-1 am i wrong?

OpenStudy (anonymous):

x is grater than -1, conversely we can say that -1 is less than x i.e. -1<x symbolicaly

OpenStudy (anonymous):

x>-1 is also true and this we have obtained while solving the inequality.

OpenStudy (anonymous):

i think it is -1<x<5

OpenStudy (amistre64):

|dw:1373123503177:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!