What is the approximate surface area of the larger cone?
A.467.5
B.267.1
C.152.7
D.817.8
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OpenStudy (anonymous):
|dw:1373124543823:dw|
OpenStudy (rsadhvika):
both cones are similar right ?
OpenStudy (anonymous):
yes
OpenStudy (amistre64):
since the surface are of a cone is equal to its base area, plus its lateral area ....
pi r^2 + .... i can never remember the lateral area without a picture
OpenStudy (amistre64):
|dw:1373125818135:dw|
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OpenStudy (amistre64):
\[arc=\theta~r\]
\[area=\frac{\theta}{2}~r^2\]
OpenStudy (rsadhvika):
surface area = \(\pi r^2 + \pi r l\)
\(r\) : radius
\(l\) : slant height
OpenStudy (amistre64):
yeah, that one :)
OpenStudy (rsadhvika):
:) may be we can first find surface area of small cone
OpenStudy (rsadhvika):
then multiply it with (sf)^2
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OpenStudy (rsadhvika):
sf = scale factor
OpenStudy (amistre64):
no need, just relate the triangles
OpenStudy (anonymous):
ok thx i was just wondering if i set up a proportion
OpenStudy (amistre64):
|dw:1373126021549:dw|
OpenStudy (rsadhvika):
yea its simple this way :)
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OpenStudy (rsadhvika):
proportion :-
\(\large \frac{21}{12} = \frac{R}{5}\)
solve R
OpenStudy (anonymous):
R is 8.75
OpenStudy (rsadhvika):
Yes, R = 8.75
OpenStudy (rsadhvika):
and slant height \(l\) = 21
OpenStudy (rsadhvika):
plug them in the formula
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