A committee of six is to be formed from nine women and three men. in how many ways can the members be chosen, to include at least one man?

I got 840, is this answer correct?

My working out:
3C1*9C5+3C2*9C4+3C3*9C3=840.

Question

A committee of six is to be formed from nine women and three men. in how many ways can the members be chosen, to include at least one man?

I got 840, is this answer correct?

My working out:
3C1*9C5+3C2*9C4+3C3*9C3=840.

souvik · Answer

i think its right !

anonymous · Answer

Can I have one more person confirm please? :)

rsadhvika · Answer

total combinations = 12C6
combinations without a single man = 9C6

combinations with atleast one man = 12C6-9C6 = 840

rsadhvika · Answer

So, good job !

anonymous · Answer

I like how you solved the problem! It's much simpler, thank you!