Which of the following statements is false? A. 3x^2 + 4x^2 = 7x^4 B. 3x^2 • 4x^2 = 12x^4 C. (3x^3)^2 = 9x^6 D. –3^2 = –9
Is D the correct answer?
Yes.
Why? Well because 3*2 is equal to what?
OH WAIT. NO.
I thought it said 3*2. >_>
-3^2 is another way of saying -3 * -3. 3 *3 = 9 A negative multiply a negative is a positive. So it's a positive 9 or just 9.
So which statement is false?
Guess and check.
Let's try C. C. (3x^3)^2 = 9x^6 What does C. (3x^3)^2 become?
9x^5?
Well let see. Another way of writing that is: C. (3x^3)(3x^3) 3 * 3 = 9 x^3 * x^3= x^6
So that is true. Though that's not the correct answer. Let's try B: B. 3x^2 • 4x^2 = 12x^4 What does 3x^2 • 4x^2 give you?
D is right for sure
D is also right \[(3x^3)^2 = 9x^6\] is true
the wrong one is the first one \[ 3x^2 + 4x^2 = 7x^4\]
for example, if \(x=10\) then \(300+400=700\) not \(300+400=70000\)
So isn't the answer either A or D?
no
only A is wrong
I am so confused right now!
why is A wrong?
@GoldPhenoix you made a mistake here -3^2 is another way of saying -3 * -3.
in fact \(-3^2=-3\times 3=-9\)
A is wrong because when you add, you do not add exponents
Really?! I never knew! o_o
3 apples and 4 apples is 7 apples 3 x squared and 4 x squared is 7 x squared
that is what i was trying to explain when i said " put \(x=10\)" if \(x=10\) then \(3x^2=300\) and \(4x^2=400\) and when you add you get \[700=7\times 10^2\] not \(7\times 10^4\)
in other words, \[3x^2+4x^2=7x^2\]
@GoldPhenoix you did so know that suppose you were asked to compute \[50-3^2\] what would you get?
50-9=41
right, so you knew that \(-3^2=-9\) or else you would have said \[50-3^2=50+9=59\] which is silly
Oh, I see.
so A is wrong...
Therefore, A is the correct answer in your question.
yeah... thanks!:)
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