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lim n-->infinity, (3^n + 2^n)/6^n
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U can write it as (1/2)^n + (1/3)^n
Now, 1^(anything) =1
and 1^n as n---> infinity = infinity That should help
Start by rewriting the bottom into 2^n+3^n. Now, you can rewrite the whole expression into a format like:
\[\frac{ a+b }{ab }\]
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which is the same thing as: \[\frac{ a }{ ab }+\frac{ b }{ab}\]
so you end up with 1/a + 1/b, where if you take the limit as x-> infinity, it approaches...you finish the rest :)
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