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Help!!! Find the equation of y, given the derivative and the indicated point on the curve? dy/dx = 2(x-1), point (3, 2)
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first expand the equation into 2x-2. Now integrate it with respect to x, you should end up with: x^2-2x+C where C is a constant
we need to make sure the copy and paste didnt eat an exponent marker
dy/dx=2(x-1) dy=2(x-1)dx integrate this. integration will give you a function(F(x)) of x and a constant y= F(x) + C so put the point in the place of X and Y and get your C do it
Now substitute the point (3,2) into it 2=(3)^2-2(3)+C and solve for C Then you should arrive at your final equation
Where should I substitute the point (3, 2)?
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Oh! I think I got it! Thank you so much!
So, should it be y = x^2 - x -1?
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