Differentiate the equation y=cosπx X sinπx
use product rule and chain rule.
show how
F = u * v If F is a function which is a product of u and v. then F' = uv'+u'v. (' indicates differentiation)
ok. show how the product rule v.u= u'v+uv'
is related to my question
You have two functions sin pi x , cos pi x. which are multiplied,.
woow thanks koushik
Be sure to apply chain rule while differentiating sin pi x and cos pi x. (after applying the product rule)
what are these boxes in your problem?
please will you show how its aplied
Caqn you draw out your problem? I cannot make out what it says.
y=cosπx X sinπx thats what i see :\
for example,\[\frac{ d }{ dx }(\sin u) = \cos u \times \frac{ d }{ dx }(u)\]
is it \[\large y = cos^2 (\pi x)\cdot sin^2 (\pi x)\]?
no jhannybean no remove ^2
did you get how to use chain rule now?
koushik show how cos pi x is diiferentiated
yeah am ok with that, the question is is there any distinct value given to pi
\[\frac{ d }{ dx}(\cos \pi x) = (-\sin \pi x) \times \frac{ d }{ dx }(\pi x)\]
yeah am done now tnx alot
you're welcome
keep in touch friend i see are more advance than me
sory wrong typing you are more advance thn me
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