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Mathematics 20 Online
OpenStudy (anonymous):

Differentiate the equation y=cos⁡πx X sin⁡πx

OpenStudy (anonymous):

use product rule and chain rule.

OpenStudy (anonymous):

show how

OpenStudy (anonymous):

F = u * v If F is a function which is a product of u and v. then F' = uv'+u'v. (' indicates differentiation)

OpenStudy (anonymous):

ok. show how the product rule v.u= u'v+uv'

OpenStudy (anonymous):

is related to my question

OpenStudy (anonymous):

You have two functions sin pi x , cos pi x. which are multiplied,.

OpenStudy (anonymous):

woow thanks koushik

OpenStudy (anonymous):

Be sure to apply chain rule while differentiating sin pi x and cos pi x. (after applying the product rule)

OpenStudy (jhannybean):

what are these boxes in your problem?

OpenStudy (anonymous):

please will you show how its aplied

OpenStudy (jhannybean):

Caqn you draw out your problem? I cannot make out what it says.

OpenStudy (jhannybean):

y=cos⁡πx X sin⁡πx thats what i see :\

OpenStudy (anonymous):

for example,\[\frac{ d }{ dx }(\sin u) = \cos u \times \frac{ d }{ dx }(u)\]

OpenStudy (jhannybean):

is it \[\large y = cos^2 (\pi x)\cdot sin^2 (\pi x)\]?

OpenStudy (anonymous):

no jhannybean no remove ^2

OpenStudy (anonymous):

did you get how to use chain rule now?

OpenStudy (anonymous):

koushik show how cos pi x is diiferentiated

OpenStudy (anonymous):

yeah am ok with that, the question is is there any distinct value given to pi

OpenStudy (anonymous):

\[\frac{ d }{ dx}(\cos \pi x) = (-\sin \pi x) \times \frac{ d }{ dx }(\pi x)\]

OpenStudy (anonymous):

yeah am done now tnx alot

OpenStudy (anonymous):

you're welcome

OpenStudy (anonymous):

keep in touch friend i see are more advance than me

OpenStudy (anonymous):

sory wrong typing you are more advance thn me

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