Question

Solve the following equations for x. Identify any extraneous solutions. Show all work.
-4sqrt6x+5=sqrt53
plz help completely stuck

Answer 1

\[-4\sqrt{6x+5}\sqrt{53}\]

Answer 2

sorry wrong problem

Answer 3

\[\sqrt{6x+5}=\sqrt{53}\]

Answer 4

square both sides, what u get ?

Answer 5

6x+5=2809

Answer 6

actually, \(\sqrt{55}^2 = 55\)

Answer 7

how did you do that?

Answer 8

\(\huge \sqrt{a}=a^{1/2}\)
\(\huge (\sqrt a)^2= a^{1/2 \times 2}=a^1 = a\)

Answer 9

ok im a little confused still

Answer 10

which step are you confused ?
\((\sqrt{anything})^2=anything\)

Answer 11

there,anything should be non-negative

Answer 12

ok i see that

Answer 13

how did you cime up with 55 though

Answer 14

oh, sorry, \(\sqrt{53}^2=53\)

Answer 15

so,
6x+5 = 53
is what u get

Answer 16

oh ok now i understand

Answer 17

can u find x from
6x+5 = 53 ?

Answer 18

x6x=48

Answer 19

6x=48

Answer 20

then i divide 6 from both sides and get x=8

Answer 21

correct!

Answer 22

i have one more can you check it for me

Answer 23

sure!

Answer 24

\[\sqrt{x+2}+4=x\]

Answer 25

\[\sqrt{x+2}=4x\]
is that correct

Answer 26

not actually,
the 4 was added on left
so, to bring it on right side, we need to subtract 4 from both sides...