Question

2x+7/x-6 plus 3x/6-x
Equation below

Answer 1

\[\frac{ 2x+7 }{ x-6 } + \frac{ 3x }{ 6-x }\]

Answer 2

Well.. Your denominators are the same just switched around. So all you have to do is add the numerators.

Answer 3

If I'm not mistaken that is.

Answer 4

don't i have a -6 and a regular 6 though?

Answer 5

6-x => -(x-6)

Answer 6

marissalovescats, you're close, but you would factor 6-x to get -1(x-6)

so

\[\large \frac{2x+7}{x-6} + \frac{3x}{6-x}\]


\[\large \frac{2x+7}{x-6} + \frac{3x}{-1(x-6)}\]


\[\large \frac{2x+7}{x-6} - \frac{3x}{x-6}\]


now you can combine the fractions

Answer 7

Ah yes. Truth ^

Answer 8

I'm a little confused on what you did?

Answer 9

do you see how 6-x = -1(x-6) ?

Answer 10

if you distribute that doesn't it make -x+6?

Answer 11

then you rearrange terms to get 6 - x

Answer 12

oh, ok

Answer 13

6 - x = 6 + (-x)

6 - x = -x + 6

6 - x = -1*x + (-1)*(-6)

6 - x = -1*(x - 6)

Answer 14

do you see how we went from

\[\large \frac{2x+7}{x-6} + \frac{3x}{-1(x-6)}\]

to

\[\large \frac{2x+7}{x-6} - \frac{3x}{x-6}\]

Answer 15

yes

Answer 16

ok great

Answer 17

thanks

Answer 18

sure thing