The time required to finish a test is normally distributed with a mean of 60 minutes and a standard deviation of 10 minutes. What is the probability that a student will finish the test in less than 70 minutes?
Lets look at our normal distribution curve:
70 minutes is one standard deviation above the mean. So you want the sum of the percentages between negative infinity and 1 standard deviation above the mean.
take the Z-score of 70. find the distribution of the percentage of the score. Than compare it to the standard distributionstable of Z scores. \[z = \frac{ 70 - 60 }{ \sigma } \] your z score is 1 so the percentage from the table of distribution .84134. you can look at the table yourself. http://www.stat.tamu.edu/~lzhou/stat302/standardnormaltable.pdf
the percentage is 84.1 % I think....
Thank you guys!
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