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Mathematics 8 Online
OpenStudy (anonymous):

Graph the following function, state the domain, range, and asymptote. y=4^(x-1)

jimthompson5910 (jim_thompson5910):

were you able to get anywhere?

OpenStudy (anonymous):

yeah i got the graph, hah thats about it

OpenStudy (marissalovescats):

I believe there are no asymptotes because there is no Vertical one because theres no denominator to set equal to zero and I just don't see a spot for a horizontal one either... But hey, I could be wrong.

OpenStudy (anonymous):

alright, thanks! and do you know the domain or range

OpenStudy (marissalovescats):

I trust @jim_thompson5910 judgement more than mine on this one.. Been awhile since I have done one of these :P Can't find these notes either, otherwise I would further assist.

OpenStudy (anonymous):

ha alright

jimthompson5910 (jim_thompson5910):

there are no vertical asymptotes because the domain is the set of all real numbers

jimthompson5910 (jim_thompson5910):

but there is a horizontal asymptote

jimthompson5910 (jim_thompson5910):

as x gets really really large in the negative direction, 4^(x-4) will get very very small (practically 0) so the horizontal asymptote is y = 0

jimthompson5910 (jim_thompson5910):

the horizontal asymptote will help you find the range

OpenStudy (marissalovescats):

^ I was told just to say there are none if it is 0 :P

jimthompson5910 (jim_thompson5910):

y = 0 is something though

jimthompson5910 (jim_thompson5910):

if there were no asymptotes at all, then it would easily cross over y = 0 at some point and 4^(x-1) would become negative somewhere but 4^(x-1) is always positive

OpenStudy (anonymous):

well is the range y >= 0?

jimthompson5910 (jim_thompson5910):

and made a typo earlier, meant to say 4^(x-1) not 4^(x-4)

jimthompson5910 (jim_thompson5910):

close, the range is y > 0 4^(x-1) never gets to zero (even though it looks like it does)

OpenStudy (anonymous):

oh, alright, thanks so much!

jimthompson5910 (jim_thompson5910):

yw

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