Graph the following function, state the domain, range, and asymptote. y=4^(x-1)
were you able to get anywhere?
yeah i got the graph, hah thats about it
I believe there are no asymptotes because there is no Vertical one because theres no denominator to set equal to zero and I just don't see a spot for a horizontal one either... But hey, I could be wrong.
alright, thanks! and do you know the domain or range
I trust @jim_thompson5910 judgement more than mine on this one.. Been awhile since I have done one of these :P Can't find these notes either, otherwise I would further assist.
ha alright
there are no vertical asymptotes because the domain is the set of all real numbers
but there is a horizontal asymptote
as x gets really really large in the negative direction, 4^(x-4) will get very very small (practically 0) so the horizontal asymptote is y = 0
the horizontal asymptote will help you find the range
^ I was told just to say there are none if it is 0 :P
y = 0 is something though
if there were no asymptotes at all, then it would easily cross over y = 0 at some point and 4^(x-1) would become negative somewhere but 4^(x-1) is always positive
well is the range y >= 0?
and made a typo earlier, meant to say 4^(x-1) not 4^(x-4)
close, the range is y > 0 4^(x-1) never gets to zero (even though it looks like it does)
oh, alright, thanks so much!
yw
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