Question

Simplify:

Answer 1

\[\frac{ 12f^6g }{ 9f^3 }\]

Answer 2

That is equal to
\[\frac{ 12f^6gf^{-3} }{ 9 }\]
so, 12 and 9 have a common divisor
and f^ a* f^-b =f^(a-b)
so your result will be...

Answer 3

\[\frac{ 4f^3 g }{ 3 }\] I think its this.

Answer 4

good job c: