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Given cos 0=-4/5, and the angle 0 is in quadrant two, find the value for sin 0.
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You can use Pythagorean identity w/ sine and cosine to find \(\sin\theta\) given \(\cos\theta\) then use the fact that \(\theta\) is in Quadrant 2.
|dw:1373165494160:dw|
the 3 via pythagoras or more likely just remembering the famous 3 - 4 - 5 right triangle then sine is opposite over hypotenuse, and it is positive since you are in quadrant 2
thanks
yw
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