Question

g(x)=1/(4th root(x^3) See the following post

How do you find the derivative of this using the differentiation formula?

Answer 1

\[g(x)=\frac{ 1 }{ \sqrt[4]{x^3} } \]

Answer 2

i would start by rewriting the denominator as x^(3/4)

Answer 3

well, this is equal to
\[g(x)= x ^{\frac{ -3 }{ 4 }}\]
So, g'(x) would be?

Answer 4

-3/4 x^-7/4

Answer 5

Use Power Rule

Answer 6

\[\large g(x) = x^{-3/4}\]Use the power rule.\[\large g'(x) = -\cfrac{3}{4} x^{-3/4-1}\]\[\large g'(x) = -\cfrac{3}{4} x^{-7/4} \]

Answer 7

\[\large -\cfrac{3}{4x^{7/4}} \ \text{or} \ -\cfrac{3}{4\sqrt[4]{x^7}} \]

Answer 8

Oooook.

Answer 9

Do you understand, @wesdg1978 ?

Answer 10

@Jhannybean Yes, I understand now, thanks for your help!

Answer 11

Awesome :)