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A Norman window has the shape of a rectangle surmounted by a semicircle. If the perimeter of the window is 32 ft, express the area A of the window as a function of the width x of the window. A(x) = ?
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|dw:1373170794857:dw| So, if x is the width, then, the area of the window will be given by the sum of the area of the rectangle and the semicircle, let's call z the heigth \[A(x)=x*z+\frac{ \pi }{ 2 }( \frac{ x }{ 2 })^2\] So we have to determinate "z" The perimeter of the window is fiven by the sum of the perimeter of the semicircle and the rectangle without a side \[32ft=P=\pi*\frac{ x }{ 2 }+2z+x\], now with that you can find z(x) and replace it on A(x) cool?
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